Maki Shijo
Suffering is the way.
Restaurant Master
☆⌒(ゝ。∂)
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« Reply #885 on: September 21, 2018, 09:20:45 AM » |
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Grade 7 was the worst for me.. Bullying and Sucidal Thoughts.. Ahhhhhhhhh
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Makima
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« Reply #886 on: September 21, 2018, 09:40:55 AM » |
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Grade 7 was the worst for me.. Bullying and Sucidal Thoughts.. Ahhhhhhhhh
Same. But such days even extended until I got kicked at the end of Grade 9 |
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"[CENSORED]" —CENSORED, Lobotomy Corporation
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BrantSteele Cast Data Contributor • January 2012 Flipline Forum User |
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Luigi
Friend of Foodini
thonking intensifies
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« Reply #887 on: September 21, 2018, 11:35:09 AM » |
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 Need to know if the integral is convergent or divergent by limit comparison test or direct comparison |
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Love Scars
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« Reply #888 on: September 21, 2018, 11:40:55 AM » |
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i prefer my new class over the middle school one
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you used to say you're in love
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Lovaho
Tomato Toppler
M-m, booboo.
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« Reply #889 on: September 21, 2018, 03:31:55 PM » |
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grade 8 was and always will be my worst year of schooling
Has. |
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I date men
But you're acting like a little boy
And no, I ain't your little toy |
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AskJoe
Global Moderator
Papa's Replacement
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« Reply #890 on: September 21, 2018, 06:18:46 PM » |
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Sine is positive in the interval 0<=x<=π, so we know,
sqrtx<=sqrtx+sinx.
Taking the reciprocal of both sides (don't forget to reverse the inequality sign) we get,
1/sqrtx>=1/(sqrtx+sinx).
Now we consider the integral
∫1/sqrtxdx where 0<=x<=π.
We can now apply the exponential property sqrtx=x^1/2.
∫1/x^(1/2)dx where 0<=x<=π.
Next, we apply another exponential identity, namely 1/x^a=x^-a. Doing this we get,
∫x^(-1/2)dx where 0<=x<=π.
Now we integrate.
2x^(1/2) from 0<=x<=π.
Finally, using the fundamental theorem of calculus we obtain
2π^(1/2)-2(0^(1/2))=2π^(1/2).
Thus the integral ∫1/sqrtxdx where 0<=x<=π converges, and since 1/sqrtx>=1/(sqrtx+sinx) the integral ∫1/(sqrtx+sinx)dx where 0<=x<=π also converges.
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HungryCat
RPF member
Burger Flipper
Back to RPF.
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« Reply #891 on: September 21, 2018, 11:56:59 PM » |
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x + (x + 2) . 5 - 10
I hate equations damnit
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An RPF member!
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Alex Amethyst
Iconic
Restaurant Master
The future is iconic
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« Reply #892 on: September 22, 2018, 02:14:08 AM » |
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x + (x + 2) . 5 - 10
I hate equations damnit
From what I understand that dot is supposed to show multiplication Therefore, we multiply everything inside the parentheses by 5, so: x + 5x + 10 - 10 From here it's: 6x + 0 or 6x And we can't go anywhere else because either you wrote something wrong (like the subtraction symbol instead of the equality symbol) or it was supposed to be like that. In case there was truly something wrong with the equation, please provide me the correct one and we can work with that  |
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KitKatExtreme [Aug 16 12:31 AM]: bleep me with a chainsaw
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Raven
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« Reply #893 on: September 22, 2018, 05:07:14 AM » |
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x + (x + 2) . 5 - 10
I hate equations damnit
Whats the question? Find x? The way you wrote it can only be simplified and not solved. |
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Love Scars
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« Reply #894 on: September 22, 2018, 06:14:22 AM » |
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Grade 7 was the worst for me.. Bullying and Sucidal Thoughts.. Ahhhhhhhhh
me with 6th grade |
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you used to say you're in love
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Lovaho
Tomato Toppler
M-m, booboo.
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« Reply #895 on: September 22, 2018, 06:28:29 AM » |
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I date men
But you're acting like a little boy
And no, I ain't your little toy |
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Alex Amethyst
Iconic
Restaurant Master
The future is iconic
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« Reply #896 on: September 22, 2018, 08:10:43 AM » |
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Whats the question? Find x?
The way you wrote it can only be simplified and not solved.
I was thinking the same thing. |
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KitKatExtreme [Aug 16 12:31 AM]: bleep me with a chainsaw
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mika
semi-active
Restaurant Master
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« Reply #897 on: September 22, 2018, 08:45:18 AM » |
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grade 8 was and always will be my worst year of schooling
I'm in grade 8 rn and I gotta say it is WORSE than 7 and 6, which I thought was the worst years... |
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Luigi
Friend of Foodini
thonking intensifies
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« Reply #898 on: September 24, 2018, 07:38:19 AM » |
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Integral of x/(4+9x^4)
Integral of 1/sqrt(6x-x^2)
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Ianiant
Restaurant Pro
Am I doing this right?
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« Reply #899 on: September 24, 2018, 04:02:37 PM » |
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I got accepted into COLLEGE!  |
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