Pages: 1 ... 63 64 [65] 66 67 ... 100   
Print
Author Topic: School  (Read 150483 times)
mika
semi-active
Restaurant Master
*

mostly here for KCP


View Profile
« Reply #960 on: September 22, 2018, 08:45:18 AM »

grade 8 was and always will be my worst year of schooling
I'm in grade 8 rn and I gotta say it is WORSE than 7 and 6, which I thought was the worst years...
Logged

vote for my entries: http://www.flipline.com/kcp20/5d6y5dgz5e7
I will never remove this in my signature:
part 1:
Kris [Feb 23 02:53 PM]:   hi matt, again xp
Matt [Feb 23 02:54 PM]:   haha hi again
Kris [Feb 23 02:55 PM]:   omg matt replied
Kris [Feb 23 02:55 PM]:   matt noticed me
Kris [Feb 23 02:55 PM]:   aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
part 2:
PastaFan3000 [Jul 07 12:40 AM]:   @matt i drew you uwu http://www.flipline.com/forum/index.php?topic=149.ms...g2452971
PastaFan3000 [Jul 07 12:40 AM]:   pls notice
Matt [Jul 07 12:43 AM]:   @PastaFan3000 awesome! Cheesy
PastaFan3000 [Jul 07 12:43 AM]:   thanks matt! Cheery
Avatars:
Mar.6 - Breakfast Slider
Mar.8 - Chiaki Nanami
Mar.20 - Toad from Super Mario 64
Apr.3 - Sonia Nevermind
Apr.14 - Mini McCoy
Apr.18 - Colonel Roy Mustang
Apr.27 - Clover
May.4 - Lieutenant Riza Hawkeye
May.11 - Mika (as a pal)
May.20 - Ryutaro Naruhodou
May.25 - Koilee
May.29 - Whippa
Jun.2 - Papa's Pastaria
Jun.7 - Spaghetti
Jun.14 - Macaroni
Jun.21 - Gnocchi
Jun.28 - Ravioli
Jul.5 - Fettuccine
Jul.12 - Penne
Jul.19 - Farfalle
Jul.26 - Radiatori
Aug.2 - Cellentani
Aug.10 - Conchiglie
Aug.16 - Stellini
Kirby
Friend of Foodini
*


thonking intensifies


View Profile
« Reply #961 on: September 24, 2018, 07:38:19 AM »

Integral of x/(4+9x^4)
Integral of 1/sqrt(6x-x^2)
Logged

Ianiant
Restaurant Pro
*


KCP2020!


View Profile
« Reply #962 on: September 24, 2018, 04:02:37 PM »

I got accepted into COLLEGE! Hooray
Logged

-Phil-
Purple - 2020
Food Critic
*


KCP Entries #3: Wendell


View Profile
« Reply #963 on: September 24, 2018, 04:07:42 PM »

Is it a huge/well known college? Also congrats!
Logged

Ianiant
Restaurant Pro
*


KCP2020!


View Profile
« Reply #964 on: September 24, 2018, 04:48:46 PM »

Is it a huge/well known college? Also congrats!

It's a university, and it's one of the better ones in the state.
Logged

AskJoe
Global Moderator
Papa's Replacement
*


View Profile
« Reply #965 on: September 24, 2018, 05:11:03 PM »

For the first one start by writing 9x^4 as (3x^2)^2.
∫x/((3x^2)^2+4)dx
Now let u=3x^2, the du=6x.
1/6∫1/(u^2+4)du
Factor 1/4 out of the denominator.
1/6∫1/((1/4)u^2+1)du
Rewrite (1/4)u^2 as ((1/2)u)^2
1/6∫1/(((1/2)u)^2+1)du
Now use the substitution v=(1/2)u, then dv=1/2du.
1/12∫1/(v^2+1)dv
Now integrate.
(1/12)tan^-1(v)+C=(1/12)tan^-1((1/2)u)+C=(1/12)tan^-1(1/2(3x^2))+C

For the second integral we will start by completing the square of the quadratic under the square root, to do this we start by factoring the minus sign.
∫1/sqrt(-(x^2-6x)dx
Rewrite the term in the parentheses as x^2-6x+9, since this would be multiplied by negative 1 we'll have to add 9 outside the parentheses.
∫1/sqrt(-(x^2-6x+9)+9)dx
We now use the fact that x^2-6x+9=(x-3)^2 to rewrite the integrand as
∫1/sqrt(-(x-3)^2+9)dx.
Now use the substitution u=x-3, then du=dx.
∫1/sqrt(9-u^2)du
Now use the substitution u=3sinθ, then du=3cosθdθ. Applying this substitution we have
∫3cosθ/sqrt(9-(3sinθ)^2)du=∫3cosθ/sqrt(9-9sin^2θ)dθ=∫3cosθ/sqrt(9(1-sin^2θ))dθ
Apply the identity sin^2θ+cos^2θ=1, and simplify.
∫3cosθ/sqrt(9cos^2θ)dθ=∫3cosθ/3cosθdθ=∫dθ
Lastly, integrate and back substitute.
θ+C=sin^-1(u/3)+C=sin^-1((x-3)/3)+C
Logged
The Gameria Expert
Restaurant Pro
*


View Profile
« Reply #966 on: September 24, 2018, 05:17:15 PM »

This is for one of my young neighbors. They told me they needed so much help with this, so I decided to post it here. They don't know what the problem is looking for and neither do I. I don't know what this is all about, but whatever. It's seems very abstract though.

Recall that
lim f(x)=L
x->c
means:
For all ϵ>0 there is a δ>0 such that for all x satisfying 0<|x−c|<δ we have that |f(x)−L|<ϵ.
What if the limit does not equal L? Think about what the means in ϵ,δ language.
Consider the following phrases:
1. ϵ>0
2. δ>0
3. 0<|x−c|<δ
4. |f(x)−L|>ϵ
5. but
6. such that for all
7. there is some
8. there is some x such that

Order these statements so that they form a rigorous assertion that:
lim f(x) =/= L.
x->c

Logged
AskJoe
Global Moderator
Papa's Replacement
*


View Profile
« Reply #967 on: September 24, 2018, 05:23:10 PM »

That's the formal definition of a limit. It's used to formally prove the value of a limit. It is more likely to be seen in a Real Analysis class than in a calculus class.
Logged
AyKooChao
Cornflake
Restaurant Legend
*


View Profile
« Reply #968 on: September 24, 2018, 05:33:56 PM »

I got accepted into COLLEGE! Hooray

Congratulations! Hooray
Logged

Randomness:
The Pencil-Staff is a powerful thing, AyChao. If you wanted to, you could rewrite history-
Look at me, I have wings!

-W117

[May 18 04:31 PM]:   AyKooChao wonders why no one is shipping the user above them
[May 18 04:33 PM]:   Monika is going to ship AyKooChao in the forum game called "Ship user above you"
[May 18 04:35 PM]:   AyKooChao scrolls down very slowly...
*sees that she's been shipped with a certain Yu-Gi-Oh character...*
AyKooChao [May 18 04:36 PM]:   Again? *insert untypeable Cheesy +  Embarrassed + Cheery + Nervous + "put that notebook down, Carrie" face here*
[May 18 04:37 PM]:   Monika bursts out of laughter
Monika [May 18 04:37 PM]:   Laugh
[May 18 04:48 PM]:   AyKooChao sits in the corner of the Shoutbox and plots her revenge...
AyKooChao [May 18 04:48 PM]:   Meh, I'll just type what I always do.

Joey x AyChao shipping incidents: 21 (counting the Shoutbox and the deleted posts) Yes, I'm keeping track.

Mystic [Dec 07 01:32 PM]:   The earth is a box of cereal.


The Gameria Expert
Restaurant Pro
*


View Profile
« Reply #969 on: September 24, 2018, 05:55:32 PM »

That's the formal definition of a limit. It's used to formally prove the value of a limit. It is more likely to be seen in a Real Analysis class than in a calculus class.

So, what would be the answer anyways? Now, I got another question from them and I don't know why they're asking me and not someone else?

The function is (sin(3x))/(x) and the table asked them to find the output of these values: -0.1, -0.01, -0.001, -0.0001, 0.0001, 0.001, 0.01, 0.1. They already figured these out.

However, they want to know this:
(c) Graph the function to see if it is consistent with your answers to parts (a) and (b). By graphing, find an interval for x near zero such that the difference between your conjectured limit and the value of the function is less than 0.01. In other words, find a window of height 0.02 such that the graph exits the sides of the window and not the top or bottom. What is the window?
Logged
AskJoe
Global Moderator
Papa's Replacement
*


View Profile
« Reply #970 on: September 24, 2018, 06:39:03 PM »

In mathematics you normally encounter two types of problems. The first type is given certain information find another piece of information. This information can be any kind of mathematical object (numbers, functions, sets, vectors, etc.). This is the kind of problem you would see in grade school. The second type of problem, and the type of problem you are asking, is given a fact, prove or disprove the fact. Any logical argument would be a suitable answer for this type of problem. Some facts you might be asked to prove are: If x is odd then x^2 is odd, sqrt2 is irrational, etc. All of these facts are trivial though their proof (namely the proof for the second fact) may not be trivial. A fact you might be asked to disprove is there exists an even prime number greater than 2. Again this fact is trivial, in fact you may already intuitively understand why it is false.

The formal definition of a limit can be intuitively understood using rectangles. Given any width you can center a rectangle of the given width centered at the limit point (the (x,y) coordinate the limit approaches) with a height of twice the functions value. The formal definition of a limit says such a rectangle will always exist if the limit exists.   
Logged
Theo
Food Critic
*



View Profile
« Reply #971 on: September 24, 2018, 07:11:41 PM »

then report them...
Logged

Kirby
Friend of Foodini
*


thonking intensifies


View Profile
« Reply #972 on: September 24, 2018, 11:34:05 PM »

Now use the substitution u=3sinθ, then du=3cosθdθ. Applying this substitution we have
∫3cosθ/sqrt(9-(3sinθ)^2)du=∫3cosθ/sqrt(9-9sin^2θ)dθ=∫3cosθ/sqrt(9(1-sin^2θ))dθ
Apply the identity sin^2θ+cos^2θ=1, and simplify.
∫3cosθ/sqrt(9cos^2θ)dθ=∫3cosθ/3cosθdθ=∫dθ
Lastly, integrate and back substitute.
θ+C=sin^-1(u/3)+C=sin^-1((x-3)/3)+C
wat
Logged

Maki Shijo
Suffering is the way.
Restaurant Master
*


☆⌒(ゝ。∂)


View Profile
« Reply #973 on: September 25, 2018, 03:09:11 AM »

x + (x + 2) . 5 - 10
I hate equations damnit
I really like these
Logged
Maki Shijo
Suffering is the way.
Restaurant Master
*


☆⌒(ゝ。∂)


View Profile
« Reply #974 on: September 25, 2018, 03:10:39 AM »

my teacher said this was easy i don't believe him
find x if 6x = 36
Another way
Just take the six down
x= 36/6=6
Logged
Pages: 1 ... 63 64 [65] 66 67 ... 100   
Print
Jump to:  













Sorry, you must have JavaScript enabled to use the Flipline Forum.